re.sub用于替换字符串中的匹配项

re.sub(pattern, repl, string, count=0)

代码

import re

phone = "2004-959-559 # 这是一个电话号码"

# 删除注释
num = re.sub(r'#.*$', "", phone)
print("电话号码:", num)

# 移除非数字的内容
num = re.sub(r'\D', "", phone)
print("电话号码:", num)


# 将匹配的数字乘以2
def double(matched):
    value = int(matched.group('value'))
    return str(value * 2)


s = 'A23G4HFD567'
print(re.sub('(?P<value>\d+)', double, s))

运行结果

电话号码: 2004-959-559 
电话号码: 2004959559
A46G8HFD1134